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Add_Two_Number.cpp
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98 lines (86 loc) · 2.14 KB
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/*
Author: Weixian Zhou, ideazwx@gmail.com
Date: June 22, 2012
Problem: Add Two Number
Difficulty: easy
Source: http://www.leetcode.com/onlinejudge
Notes:
You are given two linked lists representing two non-negative
numbers. The digits are stored in reverse order and each of
their nodes contain a single digit. Add the two numbers and
return it as a linked list.
Input: (2 -> 4 -> 3) + (5 -> 6 -> 4)
Output: 7 -> 0 -> 8
*/
#include <vector>
#include <set>
#include <climits>
#include <algorithm>
#include <iostream>
#include <cmath>
using namespace std;
struct ListNode {
int val;
ListNode *next;
ListNode(int x) : val(x), next(NULL) {}
};
class Solution {
private:
struct ListNode *head;
struct ListNode *tail;
public:
void insert_new_node(int val) {
ListNode *node = new struct ListNode(val);
node->next = NULL;
if (head == NULL) {
head = node;
}
if (tail == NULL) {
tail = node;
}
else {
tail->next = node;
tail = node;
}
}
void increase_carry(int &sum, int& carry) {
if (sum > 9) {
carry = 1;
sum = sum % 10;
}
else {
carry = 0;
}
}
ListNode *addTwoNumbers(ListNode *l1, ListNode *l2) {
string a;
string b;
int sum;
int carry = 0;
head = NULL;
tail = NULL;
while (l1 != NULL && l2 != NULL) {
sum = l1->val + l2->val + carry;
increase_carry(sum, carry);
insert_new_node(sum);
l1 = l1->next;
l2 = l2->next;
}
while (l1 != NULL) {
sum = l1->val + carry;
increase_carry(sum, carry);
insert_new_node(sum);
l1 = l1->next;
}
while (l2 != NULL) {
sum = l2->val + carry;
increase_carry(sum, carry);
insert_new_node(sum);
l2 = l2->next;
}
if (carry != 0) {
insert_new_node(carry);
}
return head;
}
};