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Search_Insert_Position.cpp
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53 lines (46 loc) · 1.02 KB
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/*
Author: Weixian Zhou, ideazwx@gmail.com
Date: Jul 18, 2012
Problem: Search Insert Position
Difficulty: easy
Source: http://www.leetcode.com/onlinejudge
Notes:
Given a sorted array and a target value, return the index if the target is
found. If not, return the index where it would be if it were inserted in order.
You may assume no duplicates in the array.
Here are few examples.
[1,3,5,6], 5 → 2
[1,3,5,6], 2 → 1
[1,3,5,6], 7 → 4
[1,3,5,6], 0 → 0
Solution:
*/
#include <vector>
#include <set>
#include <climits>
#include <algorithm>
#include <iostream>
#include <sstream>
#include <cmath>
#include <cstring>
using namespace std;
class Solution {
public:
int searchInsert(int A[], int n, int target) {
int left = 0, right = n - 1, mid, pos;
while (left <= right) {
mid = (left + right) / 2;
if (target == A[mid]) {
return mid;
}
if (target < A[mid]) {
right = mid - 1;
pos = mid;
} else {
left = mid + 1;
pos = mid + 1;
}
}
return pos;
}
};