From 8b866127047d5b503ab493678daba97376f654a0 Mon Sep 17 00:00:00 2001
From: madeleine4223 <mc4223@columbia.edu>
Date: Fri, 5 Aug 2016 15:06:27 -0400
Subject: [PATCH] started but didnt finish

---
 minesweeper.c | 47 +++++++++++++++++++++++++++++++++++++++++++++++
 1 file changed, 47 insertions(+)
 create mode 100644 minesweeper.c

diff --git a/minesweeper.c b/minesweeper.c
new file mode 100644
index 0000000..ba91c38
--- /dev/null
+++ b/minesweeper.c
@@ -0,0 +1,47 @@
+/* Write a program minesweeper.c that takes in dimensions m and n from the user and a probability p, then generates a Minesweeper board of size m x n where each cell has a probability of p to be a mine (probability is a number between 0 and 1). Each cell that is not a mine contains a number representing how many mines (above, below, left, right, and diagonal) neighbor that "safe" cell. Print the board, representing each mine as an asterisk (*).
+   Your program should check for valid input.
+   Some tips: * You may want to store your board as an integer array, with some constant value for the mines (e.g. 99), then convert the integer representation to a * for printing*/
+#include <stdio.h>
+#include <stdlib.h>
+#include <time.h>
+int main(){
+
+	int m;
+	int n;
+	printf("enter m(rows)\n");
+	scanf("%d", &m);
+	printf("enter n(colums)\n");
+	scanf("%d", &n);
+	char board[m] [n];
+	int row=0;
+	int col=0;	
+	srand(time(NULL));
+	int x;
+	float p;
+	printf("Enter a probablity\n");
+	scanf("%f", &p);
+	for (row=0;row<m;row++)
+	{	
+		for (col=0; col<n; col++)
+		{
+			board[row] [col]='x';
+		}
+	}
+	for (x=0;x<p*m*n; x++)
+	{
+		row=rand()%10+1;
+		col=rand()%10+1;
+		board [row] [col]='*';
+	}
+	for (row=0;row<m;row++)
+	{
+		for (col=0;col<n;col++)
+		{
+			printf("%c\t", board[row] [col]);
+			if(col==n-1)	
+				printf("\n");
+		}
+	}
+	printf("test");
+	return 0;
+}