Bit++.cpp

Task: The classic programming language of Bitland is Bit++. This language is so peculiar and complicated.

The language is that peculiar as it has exactly one variable, called x. Also, there are two operations:

    Operation ++ increases the value of variable x by 1.
    Operation -- decreases the value of variable x by 1. 

A statement in language Bit++ is a sequence, consisting of exactly one operation and one variable x. The statement is written without spaces, that is, it can only contain characters "+", "-", "X". Executing a statement means applying the operation it contains.

A programme in Bit++ is a sequence of statements, each of them needs to be executed. Executing a programme means executing all the statements it contains.

You're given a programme in language Bit++. The initial value of x is 0. Execute the programme and find its final value (the value of the variable when this programme is executed).
Input

The first line contains a single integer n (1 ≤ n ≤ 150) — the number of statements in the programme.

Next n lines contain a statement each. Each statement contains exactly one operation (++ or --) and exactly one variable x (denoted as letter «X»). Thus, there are no empty statements. The operation and the variable can be written in any order.
Output

Print a single integer — the final value of x.
Examples
Input
Copy

1
++X

Output
Copy

1

Input
Copy

2
X++
--X

Output
Copy

0



Solution:


#include <bits/stdc++.h>
using namespace std;	


int main(){

	#ifndef ONLINE_JUDGE
	freopen("input.txt", "r", stdin);
	freopen("output.txt", "w", stdout);
	#endif
	
    
    int n;
    cin >> n;
 
    int x = 0;
    for(int i=0;i<n;i++){
        string s;
        cin >> s;
        if(s[0] == '+')
            x++;
        if(s[0] == '-')
            x--;
        if(s[2] == '+')
            x++;
        if(s[2] == '-')
            x--;
    }
    cout << x << endl;
    return 0;
}