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SQL Examples and Solutions.sql
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2140 lines (1546 loc) · 44.9 KB
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-- Sample code file for:
--
-- Self-Guided SQL: Build Your SQL Skills with SQLite
-- Andrew Comeau
-- Copyright 2025, Comeau Software Solutions
--
-- This file contains all of the example queries and exercise solutions
-- from the book.
-- Refer to the book for references to specific databases.
-- Refer to chapters and steps shown in comments.
-- i.e. "3.2.6" refers to Chapter 3.2, step 6.
-- For more infomation, please visit the official book page at:
-- https://www.comeausoftware.com/self-guided-sql-sqlite/
--
-- Or visit the LeanPub and Amazon sales pages at:
-- https://leanpub.com/self-guided-sql
-- https://amzn.to/3HdqbBH
-- 2.2: Navigating the SQLite Console
-- 2.2.13 (Chinook):
.mode column
SELECT FirstName, LastName, Company, Phone
FROM Customers LIMIT 10;
-- 2.2.14:
SELECT first_name, last_name
FROM sakila.customer LIMIT 10;
-- 2.3 - DB Brower for SQLite
-- 2.3.7
SELECT * FROM albums
WHERE title LIKE '%greatest hits%';
-- 3.2 SELECT Basics
-- 3.2.1
SELECT Name FROM Genres;
-- 3.2.2
SELECT GenreId, Name FROM Genres;
SELECT * FROM Genres;
-- 3.2.3
SELECT LastName, FirstName, Title, HireDate
FROM Employees;
-- 3.2.4
SELECT Title FROM albums LIMIT 10;
SELECT Title FROM albums LIMIT 10 OFFSET 10;
-- 3.2.5
SELECT OrderID, ProductID, (UnitPrice * Quantity) * (1-Discount)
AS [Extended Price]
FROM [Order Details]
LIMIT 100;
-- 3.2.6
SELECT (75 - 32) / (9/5.0);
-- 3.2.7
SELECT LastName, FirstName, HireDate,
timediff('now', HireDate)
FROM employees;
-- 3.2.8
pragma table_info('employees');
-- 3.2.9
SELECT FirstName, LastName, Photo from employees
WHERE LastName = ‘Davolio’;
-- 3.2.10
SELECT FirstName, LastName, Company, PostalCode,
typeof(PostalCode)
FROM customers;
PRAGMA table_info(‘customers’);
-- 3.2.11
SELECT FirstName, LastName, iif(typeof(Company) = 'null',
'N/A', Company) AS [Company Name]
FROM Customers;
-- 3.2.12
SELECT FirstName, LastName, Country,
iif(Country IN ('United States', 'Canada'),
'North America',
iif(Country IN ('Germany', 'France', 'Italy'),
'Europe', 'Undefined')
) AS Region
FROM Customers;
-- 3.2.13
SELECT FirstName, LastName, Country,
CASE
WHEN Country IN ('United States', 'Canada')
THEN 'North America'
WHEN Country IN ('Germany', 'France', 'Italy')
THEN 'Europe'
ELSE 'Undefined'
END AS Region
FROM Customers;
-- 3.2 Challenge Solutions
-- 1.
SELECT InvoiceDate, BillingCity, BillingState, Total
FROM invoices
LIMIT 15;
-- 2.
FROM invoices
LIMIT 25 OFFSET 15;
-- 3.
SELECT Name, Composer, Milliseconds
FROM tracks
LIMIT 100;
-- 4.
SELECT * FROM Sakila.category;
-- 5.
SELECT first_name, last_name, email
FROM Sakila.customer
LIMIT 50;
-- 3.3 – Applying Filters: The WHERE clause
-- 3.3.1
SELECT * FROM albums
WHERE title LIKE '%greatest hits%';
-- 3.3.3
SELECT title FROM albums
WHERE title LIKE 'Lost, Season _';
-- 3.3.4
SELECT FirstName, LastName, Company, Address, City, State, Country, PostalCode
FROM customers
WHERE Country = 'Canada';
-- 3.3.5
WHERE Country = 'Canada'
AND City = 'Toronto';
-- 3.3.6
SELECT ProductName, QuantityPerUnit, UnitPrice
FROM Northwind.Products
WHERE UnitPrice > 100;
-- 3.3.7
SELECT ProductName, QuantityPerUnit, UnitsInStock
FROM Northwind.Products
WHERE UnitsInStock < 10;
-- 3.3.8
SELECT * FROM invoices WHERE Total BETWEEN 5 AND 14;
-- 3.3.9
SELECT LastName FROM customers
WHERE substr(LastName, 1, 1) BETWEEN 'A' AND 'C';
-- 3.3.10
SELECT LastName FROM customers
WHERE substr(LastName, 2, 2) = 'ar';
-- 3.3.11
SELECT LastName, FirstName, Title
FROM employees
WHERE LastName = 'Mitchell' OR Title = 'IT Staff';
-- 3.3.12
SELECT * FROM artists ar
WHERE NOT EXISTS
(SELECT 1 FROM albums al
WHERE al.artistid = ar.artistid);
-- 3.3.13
SELECT FirstName, LastName, Company, city
FROM Customers c
WHERE c.Country NOT IN ('USA', 'Canada');
-- 3.3.14
SELECT al.Title, ar.name
FROM albums al
INNER JOIN artists ar
ON ar.ArtistId = al.ArtistId
WHERE ar.name IN
('Eric Clapton', 'R.E.M.', 'The Doors');
-- 3.3.15
SELECT LastName, FirstName, Title
FROM employees
WHERE Title IS NOT 'IT Staff';
SELECT Name, Milliseconds
FROM tracks
WHERE Composer IS NULL;
-- 3.3.16
SELECT FirstName, LastName, State, Country
FROM customers
WHERE State IS DISTINCT FROM 'CA';
-- 3.3.17
SELECT FirstName, LastName, Company, City, State, Country
FROM Customers
WHERE Company IS NULL;
-- 3.3.18
UPDATE customers SET Company = ''
WHERE FirstName = 'Astrid' AND LastName = 'Gruber';
-- 3.3.19
SELECT FirstName, LastName, Company
FROM customers
WHERE Company IS NULL OR Company = '';
-- 3.3.20
SELECT FirstName, LastName, Company
FROM customers
WHERE nullif(Company, '') IS NULL
ORDER BY LastName;
-- 3.3.21
SELECT CustomerID, ShipName, OrderDate, ShipVia, Freight
FROM Orders
WHERE Date(OrderDate) > '1997-01-01'
AND Date(OrderDate) < '1997-12-31';
SELECT CustomerID, ShipName, OrderDate, ShipVia, Freight
FROM Orders
WHERE OrderDate > '1997-01-01'
AND OrderDate < '1997-12-31';
-- 3.3.22
SELECT Date('now');
SELECT Time('now');
SELECT DateTime('now');
SELECT JulianDay('now');
-- 3.3.23
SELECT strftime('%m/%d/%Y','now');
-- 3.3.24
SELECT LastName, FirstName, strftime('%m/%d/%Y', HireDate) AS [Date Hired]
FROM employees;
-- 3.3.25
SELECT LastName, FirstName, HireDate, DateTime(HireDate, '+5 years') AS [Five Year Anniv.]
FROM employees;
SELECT LastName, FirstName, HireDate, DateTime(HireDate, '+0000-03-00') AS [90 Day Review]
FROM employees;
SELECT LastName, FirstName, HireDate, DateTime(HireDate, 'start of month', '+1 month') AS [Benefits Start Date]
FROM employees;
-- 3.3.26
SELECT LastName, FirstName, timediff(HireDate, 'now')
AS [Time at Company]
FROM employees;
-- 3.3.27
SELECT LastName, FirstName, ROUND((JulianDay('now') - JulianDay(HireDate)) / 365.25, 1) AS [Years at Company]
FROM employees;
-- 3.3.28
SELECT LastName, FirstName, ROUND((JulianDay('now') - JulianDay(HireDate)) / 365.25, 1) AS [Years at Company]
FROM employees
WHERE [Years at Company] > 22;
-- 3.3.29
SELECT FirstName, LastName, Company
FROM customers
WHERE Company IS NULL OR Length(Company) = 0;
-- 3.3.30
SELECT title, Length(title)
FROM albums
WHERE Length(title) > 25
ORDER BY Length(title) DESC;
-- 3.3.31
SELECT CustomerId, FirstName, LastName, Email,
Instr(Email, '@')
FROM customers;
-- 3.3.32
SELECT CustomerId, FirstName, LastName, Email,
substr(Email, 1, instr(Email, '@')) || 'example.com' AS
[New Email]
FROM customers;
-- 3.3 Challenge Solutions
1.
UPDATE customers SET Company = NULL
WHERE FirstName = 'Astrid' AND LastName = 'Gruber';
2.
SELECT Title FROM albums WHERE Title LIKE '%live%';
3.
SELECT name, Composer FROM tracks
WHERE (Milliseconds BETWEEN 180000 and 240000)
AND Composer LIKE '%Van Halen%';
4.
SELECT CompanyName, Country, Fax
FROM Northwind.customers
WHERE country = 'USA' AND Fax IS NOT NULL;
5.
SELECT LastName, FirstName, Title, HomePhone, city, Region
FROM Northwind.Employees
WHERE HireDate > '1994-01-01';
6.
SELECT title, description
FROM Sakila.film
WHERE description LIKE '%drama%'
AND description NOT LIKE '%space%'
AND length(description) > 100;
7.
SELECT timediff('1980-01-01', 'now');
SELECT timediff('now', '1980-01-01');
-- 3.4 – Sorting Data: The ORDER BY Clause
-- 3.4.1
SELECT LastName, FirstName
FROM customers
WHERE Country = 'USA'
ORDER BY LastName
LIMIT 10;
-- 3.4.2
SELECT Name, Composer, Milliseconds
FROM tracks
ORDER BY Milliseconds DESC
LIMIT 15;
-- 3.4.3
SELECT CompanyName, Address, City, Country
FROM customers
WHERE Country <> 'USA'
ORDER BY country, CompanyName;
-- 3.4.4
SELECT FirstName, LastName,
Company, City, State, Country
FROM Customers
ORDER BY Company NULLS LAST;
-- 3.4.5
SELECT LastName, FirstName
FROM customers
WHERE Country = 'USA'
ORDER BY LastName COLLATE NOCASE;
-- 3.4.6
SELECT DISTINCT City, State, Country
FROM customers
ORDER BY City;
-- 3.4.7
SELECT DISTINCT ProductName
FROM invoices
WHERE Quantity >= 100
ORDER BY ProductName;
-- 3.4.8
SELECT ProductName
FROM Products
ORDER BY Length(ProductName), ProductName;
-- 3.4.9
SELECT Name, Composer, Milliseconds,
strftime('%H:%M:%S', Milliseconds / 1000, 'unixepoch') AS [Time (H:M:S)]
FROM tracks
ORDER BY Milliseconds DESC;
-- 3.4.10
SELECT OrderID, CustomerID, OrderDate,
MAX(RequiredDate, ShippedDate) as [Order Closed]
FROM Orders;
-- 3.4.11
SELECT Productid, ProductName, ReorderLevel,
MIN(ReorderLevel, 20) AS [New Reorder Level]
FROM Products;
-- 3.4 Challenge Solutions
1.
SELECT Name, Composer, Milliseconds
FROM tracks
WHERE Composer IS NOT NULL
ORDER BY Milliseconds DESC
LIMIT 15;
2.
SELECT Name FROM artists ORDER BY Name;
3.
SELECT Name FROM artists
WHERE Name LIKE 'The%' ORDER BY Name;
4.
SELECT CompanyName, Fax
FROM Customers
WHERE fax IS NOT NULL
ORDER BY CompanyName;
5.
SELECT title, description, length, special_features
FROM film
WHERE special_features LIKE '%deleted scenes%'
ORDER BY length DESC
LIMIT 50;
-- 3.5 – Joining Tables
-- 3.5.1
SELECT al.title, ar.name as [Artist]
FROM albums al
INNER JOIN artists ar
ON ar.ArtistId = al.ArtistId
ORDER BY al.Title;
-- 3.5.2
SELECT ar.ArtistId, ar.name as [Artist], al.title
FROM artists ar
LEFT OUTER JOIN albums al
ON al.ArtistId = ar.ArtistId
ORDER BY al.Title;
-- 3.5.3
SELECT c.LastName, c.FirstName, concat(e.LastName, ', ', e.FirstName) AS [Support Rep]
FROM customers c
LEFT JOIN employees e
ON e.EmployeeId = c.SupportRepId;
-- 3.5.5
SELECT c.LastName, c.FirstName, concat(e.LastName, ', ', e.FirstName) AS [Support Rep]
FROM employees e
RIGHT JOIN customers c
ON e.EmployeeId = c.SupportRepId;
-- 3.5.6
SELECT c.LastName, c.FirstName, concat(e.LastName, ', ', e.FirstName) AS 'Support Rep'
FROM employees e
FULL JOIN customers c
ON e.EmployeeId = c.SupportRepId
WHERE c.LastName IS NULL or e.LastName IS NULL;
-- 3.5.7
SELECT e.LastName, e.FirstName, concat(m.LastName, ', ', m.FirstName) as [Reporting to:]
FROM Employees e
INNER JOIN Employees m
ON m.EmployeeId = e.ReportsTo;
-- 3.5.8
SELECT concat(e.LastName, ', ', e.FirstName) AS [Sales Rep],c.CategoryName
FROM employees e
CROSS JOIN Categories c
WHERE e.title = 'Sales Representative';
-- 3.5.9
SELECT al.title, ar.name as [Artist]
FROM albums al
NATURAL JOIN artists ar
ORDER BY title;
-- 3.5.10
SELECT f.title, f.description, f.length, f.rating
FROM film f
INNER JOIN film_category fc
ON fc.film_id = f.film_id
INNER JOIN category c
ON c.category_id = fc.category_id
WHERE c.name = 'Action';
-- 3.5.11
SELECT concat(a.first_name, ' ', last_name) AS [Actor]
FROM actor a
INNER JOIN film_actor fa
ON fa.actor_id = a.actor_id
INNER JOIN film f
ON fa.film_id = f.film_id
WHERE f.title = 'CADDYSHACK JEDI';
-- 3.5.12
SELECT a.actor_id, f.title
FROM actor a
INNER JOIN film_actor fa
ON fa.actor_id = a.actor_id
INNER JOIN film f
ON fa.film_id = f.film_id
WHERE a.first_name = 'ED'
AND a.last_name = 'CHASE';
-- 3.5.13
SELECT cl.*, c.email
FROM customer_list cl
INNER JOIN customer c
ON c.customer_id = cl.ID;
-- 3.5.14
SELECT cl.*, email, sa.address, sa.address2, sa.postal_code, sa.phone
FROM customer_list cl
INNER JOIN customer c
ON c.customer_id = cl.ID
INNER JOIN store s
ON s.store_id = cl.SID
INNER JOIN address sa
ON sa.address_id = s.address_id;
-- 3.5.15
SELECT cl.*, email, concat(sa.address,' ', sa.address2, ', ' , city.city, ' ', sa.postal_code, ', ', co.country) AS [Store Location], sa.phone as 'Store Phone'
FROM customer_list cl
INNER JOIN customer c
ON c.customer_id = cl.ID
INNER JOIN store s
ON s.store_id = cl.SID
INNER JOIN address sa
ON sa.address_id = s.address_id
INNER JOIN city
ON city.city_id = sa.address_id
INNER JOIN country co
ON co.country_ID = city.country_id
ORDER BY c.last_name;
-- 3.5.16
SELECT concat_ws(', ',e.LastName, e.FirstName) AS [Employee],
concat_ws(', ',m.LastName, m.FirstName) AS [Reporting to]
FROM Employees e
INNER JOIN Employees m
ON m.EmployeeId = e.ReportsTo;
-- 3.5.17
SELECT concat(LastName, ', ', FirstName) AS [Name], Company,
concat_ws(', ', Address, City, State, Country,
PostalCode) AS [Mailing Address]
FROM customers;
-- 3.5.18
SELECT concat(LastName, ', ', FirstName) AS [Name],
rtrim(BirthDate, ' 00:00:00') AS [Birthdate]
FROM employees;
-- 3.5.19
SELECT concat(LastName, ', ', FirstName) AS [Name],
ltrim(Phone, '+1 ') AS [Phone]
FROM employees;
-- 3.5 Challenge Solutions
1.
SELECT i.InvoiceId, i.InvoiceDate, concat(c.LastName, ', ', c.FirstName) AS [Customer], c.Company, c.email
FROM invoices i
INNER JOIN customers c
ON c.CustomerId = i.CustomerId
WHERE i.InvoiceDate < '2010-01-01'
ORDER BY i.InvoiceDate;
2.
SELECT f.title, r.rental_date, r.return_date, i.inventory_id
FROM Sakila.film f
inner JOIN Sakila.inventory i
ON i.film_id = f.film_id
INNER JOIN rental r
ON r.inventory_id = i.inventory_id
WHERE f.title = 'ANTITRUST TOMATOES'
OR f.film_id = 29;
3.
SELECT p.ProductName, c.description, s.CompanyName
FROM Northwind.Products p
INNER JOIN Categories c
ON c.CategoryID = p.CategoryID
INNER JOIN Suppliers s
ON s.SupplierID = p.SupplierID
ORDER BY c.description, p.ProductName;
4.
SELECT o.OrderID, c.CompanyName, o.OrderDate, o.ShippedDate, o.Freight
FROM Northwind.Orders o
INNER JOIN Northwind.Shippers s
ON s.ShipperID = o.ShipVia
INNER JOIN Northwind.Customers c
ON c.CustomerId = o.CustomerId
WHERE s.CompanyName = 'Speedy Express';
5.
SELECT i.InvoiceDate, t.name, a.title, g.name
FROM customers c
INNER JOIN invoices i
ON i.customerId = c.CustomerId
INNER JOIN invoice_items ii
ON ii.InvoiceId = i.InvoiceId
INNER JOIN tracks t
ON t.TrackId = ii.TrackId
INNER JOIN albums a
ON a.AlbumId = t.AlbumId
INNER JOIN genres g
ON g.GenreId = t.GenreId
WHERE c.customerid = 27
order by i.InvoiceDate;
-- 3.6 – Defining Groups: The GROUP BY Clause
-- 3.6.1
SELECT COUNT(*) AS [Invoices], concat(c.LastName, ', ', c.FirstName) AS [Customer]
FROM invoices i
INNER JOIN customers c
ON c.CustomerId = i.InvoiceId
GROUP BY i.CustomerId
ORDER BY count(*) DESC;
-- 3.6.2
SELECT COUNT(*)
FROM customers
WHERE country = 'Canada';
SELECT COUNT(DISTINCT country)
FROM customers;
SELECT DISTINCT Country
FROM customers;
-- 3.6.3
SELECT COUNT(*) AS [Invoices], c.Country
FROM invoices i
INNER JOIN customers c
ON c.CustomerId = i.InvoiceId
GROUP BY c.country
ORDER BY [Invoices] DESC;
-- 3.6.4
SELECT COUNT(company)
FROM customers;
-- 3.6.5
SELECT t.AlbumId, a.title, COUNT(*) AS track_count
FROM tracks t
INNER JOIN albums a
ON a.AlbumId = t.AlbumId
GROUP BY t.AlbumId;
-- 3.6.6
SELECT CategoryName, ROUND(AVG(UnitPrice), 2) AS [Average Price]
FROM [Alphabetical List of Products]
GROUP BY CategoryName
ORDER BY [Average Price] DESC;
-- 3.6.7
SELECT GenreId,
ROUND (AVG(Bytes / 1024 / 1024), 2) AS [Avg Size (MB)]
FROM tracks
GROUP BY GenreId;
-- 3.6.8
SELECT t.GenreId, g.name, ROUND(AVG(Bytes / 1024 / 1024), 2) AS [Avg Size (MB)]
FROM tracks t
INNER JOIN genres g
ON g.GenreId = t.GenreId
GROUP BY t.GenreId, g.name;
-- 3.6.9
SELECT * FROM invoices;
SELECT InvoiceDate, BillingCountry FROM invoices;
SELECT MIN(InvoiceDate) AS [First Invoice], BillingCountry
FROM invoices
GROUP BY BillingCountry
ORDER BY [First Invoice];
-- 3.6.10
SELECT TOTAL(replacement_cost) FROM film;
-- 3.6.11
SELECT GROUP_CONCAT(DISTINCT BillingCity) AS Cities,
BillingCountry
FROM invoices
GROUP BY BillingCountry;
-- 3.6.12
SELECT CategoryName, ROUND(AVG(UnitPrice), 2) AS [Average Price]
FROM [Alphabetical List of Products]
GROUP BY CategoryName
HAVING [Average Price] > 25
ORDER BY [Average Price] DESC;
-- 3.6.13
SELECT strftime('%m-%Y', ShippedDate) AS Month, ROUND(SUM(Subtotal), 2) as [Monthly Sales]
FROM [Summary of Sales By Year]
GROUP BY Month
HAVING [Monthly Sales] > 75000
ORDER BY ShippedDate;
-- 3.6.14
SELECT OrderID, round(UnitPrice, 2), round(Quantity, 2),
round(Discount, 2), round(Freight)
FROM invoices
LIMIT 100;
-- 3.6.15
SELECT OrderID, printf('%.2f', UnitPrice), Quantity, printf('%.2f', Discount), printf('%.2f', ExtendedPrice),
printf('%.2f', Freight)
FROM invoices
LIMIT 100;
-- 3.6.16
SELECT printf('%s - %s ($%.2f)', ProductID, ProductName,
UnitPrice) AS ProductInfo
FROM Products
LIMIT 100;
-- 3.6 Challenge Solutions
1.
SELECT TOTAL(f.replacement_cost)
FROM inventory i
INNER JOIN film f
ON f.film_id = i.film_id;
2.
SELECT p.PlaylistId, p.name, count(pt.trackID) AS [Track Count]
FROM playlists p
INNER JOIN playlist_track pt
ON pt.PlaylistId = p.PlaylistId
GROUP BY p.PlaylistId, p.name
HAVING [Track Count] = 1
ORDER BY [Track Count] DESC;
3.
SELECT p.PlaylistId, p.name, count(pt.trackID) AS [Track Count]
FROM playlists p
INNER JOIN playlist_track pt
ON pt.PlaylistId = p.PlaylistId
INNER JOIN tracks t
ON t.TrackId = pt.TrackId
WHERE t.Composer LIKE '%Ballard%'
GROUP BY p.PlaylistId, p.name
ORDER BY [Track Count] DESC;
4.
SELECT e.EmployeeId, concat(e.FirstName, ' ', e.LastName) as [Employee], count(*) as [Order Count]
FROM Orders o
INNER JOIN Employees e
ON e.EmployeeId = o.EmployeeId
WHERE o.OrderDate > '1996-12-31'
AND o.OrderDate < '1997-04-01'
GROUP BY e.EmployeeId, [Employee]
ORDER BY [Order Count] DESC;
5.
SELECT strftime('%m-%Y', OrderDate) AS [Month], ROUND(SUM(ExtendedPrice + Freight), 2) AS [Month Total]
FROM Invoices
GROUP BY [Month]
ORDER BY OrderDate;
-- 3.7 – Breaking it Down: Subqueries and Common Table Expressions
-- 3.7.1
SELECT ii.InvoiceId
FROM invoice_items ii
GROUP BY ii.InvoiceId
HAVING COUNT(ii.TrackID) > 12 ;
-- 3.7.2
SELECT FirstName, LastName, Address, City, State
FROM Customers c
INNER JOIN Invoices i
ON i.CustomerId = c.CustomerId
WHERE i.InvoiceId IN
(select ii.InvoiceId
FROM invoice_items ii
GROUP BY ii.InvoiceId
HAVING COUNT(ii.TrackID) > 12);
-- 3.7.3
SELECT FirstName, LastName, Address, City, State
FROM Customers c
INNER JOIN invoices i
ON i.CustomerId = c.CustomerId
INNER JOIN
(SELECT ii.InvoiceId
FROM invoice_items ii
GROUP BY ii.InvoiceId
HAVING count(ii.TrackID) > 12) AS LI
ON LI.InvoiceId = i.InvoiceId;
-- 3.7.4
SELECT c.customer_id
FROM Customer c
INNER JOIN Payment p
ON p.customer_id = c.customer_id
GROUP BY c.customer_id
HAVING TOTAL(p.amount) > 150;
-- 3.7.5
SELECT *
FROM customer_list cl
WHERE cl.id IN
(SELECT c.customer_id
FROM Customer c
INNER JOIN payment p
ON p.customer_id = c.customer_id
GROUP BY c.customer_id
HAVING TOTAL(p.amount) > 150)
ORDER BY cl.name;
-- 3.7.6
WITH [Order Totals] AS
(SELECT OrderID, TOTAL(ExtendedPrice) AS OT
FROM [Order Details Extended]
GROUP BY OrderID)
SELECT OrderID, PRINTF("%.2f", OT) AS [Order Total]
FROM [Order Totals]
ORDER BY OT DESC
LIMIT 20;
-- 3.7.7
SELECT strftime('%Y-%m', OrderDate) AS Period, EmployeeId, COUNT(OrderID) as [Order Count]
FROM Orders
GROUP BY Period, EmployeeId;
-- 3.7.8
WITH [MonthlyTotals] AS
(SELECT strftime('%Y-%m', OrderDate) AS Period,
EmployeeId, COUNT(OrderID) as [Order Count]
FROM Northwind.Orders
GROUP BY Period, EmployeeId)
SELECT Period, MAX([Order Count]) AS [Max Orders],
mt.EmployeeId, e.FirstName, e.LastName
FROM MonthlyTotals mt
INNER JOIN Northwind.Employees e
ON e.EmployeeId = mt.EmployeeId
GROUP BY Period;
-- 3.7 Big Spenders Solutions
SELECT cl.*
FROM customer_list cl
INNER JOIN
(SELECT c.customer_id
FROM Customer c
INNER JOIN payment p
ON p.customer_id = c.customer_id
GROUP BY c.customer_id
HAVING TOTAL(p.amount) > 150) AS HighSpend
ON HighSpend.customer_id = cl.ID
ORDER BY cl.name;
-- 3.7.9
WITH RECURSIVE counter(x) AS (
SELECT 1
UNION ALL
SELECT x + 1 FROM counter WHERE x < 10