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AddTwoNumbers.java
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169 lines (153 loc) · 5.1 KB
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package com.cier.solution.list;
import com.cier.solution.common.ListNode;
import java.math.BigInteger;
/**
* 两数相加
* https://leetcode-cn.com/problems/add-two-numbers/
*/
public class AddTwoNumbers {
/**
* Runtime: 2 ms, faster than 94.85% of Java online submissions for Add Two Numbers.
* Memory Usage: 43.5 MB, less than 87.44% of Java online submissions for Add Two Numbers.
* @param l1
* @param l2
* @return
*/
public ListNode addTwoNumbers3(ListNode l1, ListNode l2) {
ListNode head = null;
ListNode tail = null;
// one 用来判断是否应该进位
boolean one = false;
while (l1 != null || l2 != null) {
int val = 0;
if (l1 != null) {
val += l1.val;
l1 = l1.next;
}
if (l2 != null) {
val += l2.val;
l2 = l2.next;
}
if (one) {
val += 1;
}
// 判断是否进位
if (val >= 10) {
val -= 10;
one = true;
}else {
one = false;
}
if (head == null) {
head = tail = new ListNode(val);
}else {
tail.next = new ListNode(val);
tail = tail.next;
}
}
if (one) {
tail.next = new ListNode(1);
}
return head;
}
/**
* Runtime: 2 ms, faster than 94.96% of Java online submissions for Add Two Numbers.
* Memory Usage: 44.1 MB, less than 86.22% of Java online submissions for Add Two Numbers.
* @param l1
* @param l2
* @return
*/
public ListNode addTwoNumbers2(ListNode l1, ListNode l2) {
ListNode l3 = null;
if (l1 == null && l2 == null) {
return null;
} else if (l1 == null && l2 != null) {
return l2;
} else if (l1 != null && l2 == null) {
return l1;
} else {
if (l1.val + l2.val < 10) {
l3 = new ListNode(l1.val + l2.val);
l3.next = addTwoNumbers2(l1.next, l2.next);
}else {
l3 = new ListNode(l1.val + l2.val - 10);
l3.next = addTwoNumbers2(l1.next, addTwoNumbers2(l2.next, new ListNode(1)));
}
}
return l3;
}
/**
* Runtime: 14 ms, faster than 52.43% of Java online submissions for Add Two Numbers.
* Memory Usage: 37.6 MB, less than 99.88% of Java online submissions for Add Two Numbers.
*
* @param l1
* @param l2
* @return
*/
public ListNode addTwoNumbers1(ListNode l1, ListNode l2) {
String numStr1 = String.valueOf(l1.val);
String numStr2 = String.valueOf(l2.val);
while (l1.next != null) {
numStr1 += String.valueOf(l1.next.val);
l1 = l1.next;
}
while (l2.next != null) {
numStr2 += String.valueOf(l2.next.val);
l2 = l2.next;
}
BigInteger num1 = new BigInteger(new StringBuffer(numStr1).reverse().toString());
BigInteger num2 = new BigInteger(new StringBuffer(numStr2).reverse().toString());
BigInteger sum = num1.add(num2);
String sumStr = new StringBuffer(String.valueOf(sum)).reverse().toString();
ListNode head = new ListNode(0);
ListNode dummy = head;
for (int i = 0; i < sumStr.length(); i++) {
head.next = new ListNode(Integer.parseInt(String.valueOf(sumStr.charAt(i))));
head = head.next;
}
return dummy.next;
}
public ListNode addTwoNumbers(ListNode l1, ListNode l2) {
ListNode head = new ListNode(0);
ListNode result = head;
int carry = 0;
while (l1 != null && l2 != null) {
result.next = new ListNode((l1.val + l2.val + carry) % 10);
carry = l1.val + l2.val + carry >= 10 ? 1 : 0;
l1 = l1.next;
l2 = l2.next;
result = result.next;
}
while (l1 != null) {
result.next = new ListNode((l1.val + carry) % 10);
carry = l1.val + carry >= 10 ? 1 : 0;
result = result.next;
l1 = l1.next;
}
while (l2 != null) {
result.next = new ListNode((l2.val + carry) % 10);
carry = l2.val + carry >= 10 ? 1 : 0;
result = result.next;
l2 = l2.next;
}
if (carry != 0) {
result.next = new ListNode(carry);
}
return head.next;
}
public static void main(String[] args) {
ListNode node1 = new ListNode(2);
ListNode node2 = new ListNode(4);
ListNode node3 = new ListNode(5);
node1.next = node2;
node2.next = node3;
ListNode node4 = new ListNode(6);
ListNode node5 = new ListNode(7);
ListNode node6 = new ListNode(8);
node4.next = node5;
node5.next = node6;
AddTwoNumbers addTwoNumbers = new AddTwoNumbers();
ListNode node = addTwoNumbers.addTwoNumbers(node1, node4);
System.out.println();
}
}