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binaryTreeLevelOrderTraversal
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34 lines (33 loc) · 1011 Bytes
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/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode() : val(0), left(nullptr), right(nullptr) {}
* TreeNode(int x) : val(x), left(nullptr), right(nullptr) {}
* TreeNode(int x, TreeNode *left, TreeNode *right) : val(x), left(left), right(right) {}
* };
*/
class Solution {
public:
vector<vector<int>> levelOrder(TreeNode* root) {
vector<vector<int>> traversal;
if (root==NULL) return traversal;
queue <TreeNode*> q;
q.push(root);
while (!q.empty()){
vector <int> level;
int size = q.size();
for (int i=0; i<size; i++){
TreeNode* cur = q.front();
q.pop();
level.push_back(cur->val);
if(cur->left) q.push(cur->left);
if(cur->right) q.push(cur->right);
}
traversal.push_back(level);
}
return traversal;
}
};