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P.cpp
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74 lines (68 loc) · 2.02 KB
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// nhi btane ka h bhidu
#include<bits/stdc++.h>
using namespace std;
#define ll long long int
#define mod 1000000007
#define w(t) while(t--)
#define yes cout<<"Yes\n"
#define no cout<<"No\n"
#define PI 3.14159265358979323846
#define el cout<<endl;
#define fastIO ios_base::sync_with_stdio(false);cin.tie(nullptr);cout.tie(nullptr)
const ll MAX=3e6+10;
const ll INF=2e18;
#define INPUT_OUTPUT {\
freopen("input.txt","r",stdin);\
freopen("output.txt","w",stdout);\
}
// concept of tree dp.
vector<ll> solve(vector<vector<ll>> &gp, vector<bool> &vis, ll u, ll v) {
vis[u] = true;
// for leaf node we have two choices, black & white.
ll white = 1LL, black = 1LL;
for(ll x : gp[u]) {
if(x == v || vis[x]) continue;
vector<ll> ways = solve(gp, vis, x, u);
// when root is black, child can only have white nodes, so multiple white nodes of each children.
black = ((ways[0]) * black) % mod;
// when root is white, child can have two choices: white & black, so add both the choices & multiply with each children.
white = ((ways[0] + ways[1]) * white) % mod;
}
// return both possible ways.
return {white % mod, black % mod};
}
// logical code of program starts here.
void solve(int T) {
ll n;
cin>>n;
vector<vector<ll>> gp(n, vector<ll>());
for(int i = 0; i < n - 1; i++) {
ll u, v;
cin>>u>>v;
u--;
v--;
gp[u].push_back(v);
gp[v].push_back(u);
}
ll ans = 0;
vector<bool> vis(n, false);
for(ll i = 0; i < n; i++) {
if(vis[i]) continue;
vector<ll> x = solve(gp, vis, i, -1);
// If tree is not connected, in that case check for each tree or we can say for each component and add their answers.
ans = (ans + x[0] + x[1]) % mod;
}
cout<<ans<<endl;
}
// mian function
int main() {
#ifndef ONLINE_JUDGE
INPUT_OUTPUT;//file handlings
#endif
fastIO;// fast input output
int t;
t=1;
//cin>>t;
for(int i = 1; i <= t; i++) solve(i);
return 0;
}