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704.binary-search.cpp
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71 lines (70 loc) · 1.46 KB
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/*
* @lc app=leetcode id=704 lang=cpp
*
* [704] Binary Search
*
* https://leetcode.com/problems/binary-search/description/
*
* algorithms
* Easy (55.22%)
* Likes: 6189
* Dislikes: 136
* Total Accepted: 1.2M
* Total Submissions: 2.1M
* Testcase Example: '[-1,0,3,5,9,12]\n9'
*
* Given an array of integers nums which is sorted in ascending order, and an
* integer target, write a function to search target in nums. If target exists,
* then return its index. Otherwise, return -1.
*
* You must write an algorithm with O(log n) runtime complexity.
*
*
* Example 1:
*
*
* Input: nums = [-1,0,3,5,9,12], target = 9
* Output: 4
* Explanation: 9 exists in nums and its index is 4
*
*
* Example 2:
*
*
* Input: nums = [-1,0,3,5,9,12], target = 2
* Output: -1
* Explanation: 2 does not exist in nums so return -1
*
*
*
* Constraints:
*
*
* 1 <= nums.length <= 10^4
* -10^4 < nums[i], target < 10^4
* All the integers in nums are unique.
* nums is sorted in ascending order.
*
*
*/
// @lc code=start
class Solution
{
public:
int search(vector<int> &nums, int target)
{
int left = 0, right = nums.size() - 1, mid;
while (left <= right)
{
mid = (left + right) / 2;
if (nums[mid] == target)
return mid;
if (nums[mid] < target)
left = mid + 1;
else
right = mid - 1;
}
return -1;
}
};
// @lc code=end