[Benchmark] DeepSeek V4.1-Flash on an RTX 4090 Laptop 16 GB with 94 GiB RAM: the release engine package 0.1.52 (sm_89), IST-DAS 2.25 and 2.00 bpw

bench/results/2026-10-27-community-rtx-4090-laptop-deepseek-v4.1/coding/ds200-faster.jsonl

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+{"label": "ds200-faster", "task": 1, "elapsed_s": 44.8, "prompt_n": 78, "prompt_tok_s": 19.5, "gen_n": 635, "decode_tok_s": 15.6, "draft_n": 0, "draft_n_accepted": 0, "finish": "stop", "thinking_chars": 1910, "answer_chars": 525, "reasoning": "We need answer to user. They ask \"Write a Python function that merges overlapping intervals in a list of [start, end] pairs, with a short docstring and two tests. Keep it compact.\" Need provide code. Need think if they want function and tests. We can give compact Python. Need ensure merges overlapping intervals, maybe touching? \"overlapping\" usually if start <= current_end, merge. Could include touching intervals? If intervals [1,2],[2,3] maybe overlap at point, merge. Standard merge intervals if start <= last_end. We can write.\n\nNeed maybe include docstring, two tests. Compact. Should be standalone? Include function and tests. Maybe use assert in __main__. Need perhaps mention sorted by start. Code:\n\ndef merge_intervals(intervals):\n    \"\"\"Merge overlapping [start, end] intervals.\"\"\"\n    merged = []\n    for start, end in sorted(intervals, key=lambda x: x[0]):\n        if merged and start <= merged[-1][1]:\n            merged[-1][1] = max(merged[-1][1], end)\n        else:\n            merged.append([start, end])\n    return merged\n\nif __name__ == \"__main__\":\n    assert merge_intervals([[1,3],[2,6],[8,10],[15,18]]) == [[1,6],[8,10],[15,18]]\n    assert merge_intervals([[1,4],[4,5]]) == [[1,5]]\n\nNeed consider list of intervals maybe not sorted. Good.\n\nThe user mentions \"[ds200-faster task 1 4d11dad7]\" likely benchmark. Need answer just code maybe. They want two tests. Keep compact. Include no explanation maybe. Need ensure docstring short. Could include type hints? compact. Use `from typing import List`? unnecessary.\n\nLet's craft final answer with code block. Need maybe mention tests as asserts. Good.\n\nNeed consider if intervals with start and end inclusive? The condition start <= merged[-1][1] merges adjacent/touching. If overlapping means only strict overlap, use start < last_end. But standard merges adjacent too. Fine.\n\nNeed maybe handle empty. The function returns []. Good.\n\nFinal.", "answer": "```python\ndef merge_intervals(intervals):\n    \"\"\"Merge overlapping [start, end] intervals.\"\"\"\n    merged = []\n    for start, end in sorted(intervals, key=lambda x: x[0]):\n        if merged and start <= merged[-1][1]:\n            merged[-1][1] = max(merged[-1][1], end)\n        else:\n            merged.append([start, end])\n    return merged\n\n\nif __name__ == \"__main__\":\n    assert merge_intervals([[1, 3], [2, 6], [8, 10], [15, 18]]) == [[1, 6], [8, 10], [15, 18]]\n    assert merge_intervals([[1, 4], [4, 5]]) == [[1, 5]]\n```"}
+{"label": "ds200-faster", "task": 2, "elapsed_s": 96.1, "prompt_n": 78, "prompt_tok_s": 19.6, "gen_n": 1606, "decode_tok_s": 17.4, "draft_n": 0, "draft_n_accepted": 0, "finish": "stop", "thinking_chars": 3647, "answer_chars": 2151, "reasoning": "We need answer implement LRU cache in Python get/put O(1), no OrderedDict/functools. Include three short tests. Need be careful. Need likely provide code. User says \"[ds200-faster task 2 4c0cf092]\" maybe task id. Need implement class. Should we output code only? We can give explanation concise.\n\nNeed design: classic doubly linked list + dict. O(1). Class LRUCache with capacity. Need get(key): if not in map return -1? Typically LRU cache LeetCode uses get returns -1. put updates. Need include three short tests. We can use asserts or print. No OrderedDict/functools. Need avoid importing? Could use dataclass? Not needed. Use Node class with prev next. Dict key -> node. Sentinel? Could use head and tail sentinels. Need O(1) add/remove.\n\nImplementation details:\nclass Node:\n    __slots__ = (\"key\",\"value\",\"prev\",\"next\")\n    def __init__(self,key=None,value=None):\n        self.key=key; self.value=value; self.prev=None; self.next=None\n\nclass LRUCache:\n    def __init__(self, capacity):\n        self.capacity=capacity\n        self.cache={}\n        self.head=Node()\n        self.tail=Node()\n        self.head.next=self.tail\n        self.tail.prev=self.head\n\n    def _remove(self,node):\n        prev=node.prev; nxt=node.next\n        prev.next=nxt\n        nxt.prev=prev\n\n    def _add_to_front(self,node):\n        node.prev=self.head\n        node.next=self.head.next\n        self.head.next.prev=node\n        self.head.next=node\n\n    def get(self,key):\n        if key not in self.cache: return -1\n        node=self.cache[key]\n        self._remove(node)\n        self._add_to_front(node)\n        return node.value\n\n    def put(self,key,value):\n        if key in self.cache:\n            node=self.cache[key]\n            node.value=value\n            self._remove(node)\n            self._add_to_front(node)\n            return\n        node=Node(key,value)\n        self.cache[key]=node\n        self._add_to_front(node)\n        if len(self.cache)>self.capacity:\n            lru=self.tail.prev\n            self._remove(lru)\n            del self.cache[lru.key]\n\nPotential capacity 0? If capacity 0, put: after add, len>0, remove tail.prev = node, delete. Works? If capacity 0, add node to front, len=1>0 remove node, del cache key. Then head next tail. Get returns -1. Good. But capacity maybe positive. Need ensure _remove sentinel? only called on actual node or tail.prev. Fine.\n\nTests:\ncache = LRUCache(2)\ncache.put(1,1); cache.put(2,2)\nassert cache.get(1)==1\ncache.put(3,3)\nassert cache.get(2)==-1\ncache.put(4,4)\nassert cache.get(1)==-1\nassert cache.get(3)==3\nassert cache.get(4)==4\n\nSecond: update and eviction:\nc = LRUCache(2)\nc.put(1,10); c.put(2,20); c.put(1,11); c.put(3,30)\nassert c.get(2)==-1\nassert c.get(1)==11\nassert c.get(3)==30\n\nThird: capacity 1:\nc = LRUCache(1); c.put(1,1); c.put(2,2); assert c.get(1)==-1; assert c.get(2)==2. Also maybe get missing -1.\n\nNeed include tests \"three short tests\" maybe as functions or asserts. Code no imports. Good.\n\nNeed maybe mention O(1) average due dict. Could include full script.\n\nPotential issue: Node.__slots__ no need sentinel key/value default None. Fine. Need not use collections or functools. Good.\n\nNeed answer in final. Could include code block with class and tests. Explanation maybe minimal. Desired oververbosity 5. Should be enough.\n\nLet's craft final with complete code and brief note. Ensure no OrderedDict/functools. Use only built-ins. Include three short tests. Maybe no print except final? \"Include three short tests\" use asserts. Need maybe if tests are run, no output. Fine.\n\nNeed perhaps class name LRUCache. Include type hints? No imports. We can use typing? Avoid.\n\nLet's final.", "answer": "```python\nclass Node:\n    __slots__ = (\"key\", \"value\", \"prev\", \"next\")\n\n    def __init__(self, key=None, value=None):\n        self.key = key\n        self.value = value\n        self.prev = None\n        self.next = None\n\n\nclass LRUCache:\n    def __init__(self, capacity):\n        self.capacity = capacity\n        self.cache = {}\n        self.head = Node()\n        self.tail = Node()\n        self.head.next = self.tail\n        self.tail.prev = self.head\n\n    def _remove(self, node):\n        prev_node = node.prev\n        next_node = node.next\n        prev_node.next = next_node\n        next_node.prev = prev_node\n\n    def _add_to_front(self, node):\n        node.prev = self.head\n        node.next = self.head.next\n        self.head.next.prev = node\n        self.head.next = node\n\n    def get(self, key):\n        if key not in self.cache:\n            return -1\n\n        node = self.cache[key]\n        self._remove(node)\n        self._add_to_front(node)\n        return node.value\n\n    def put(self, key, value):\n        if key in self.cache:\n            node = self.cache[key]\n            node.value = value\n            self._remove(node)\n            self._add_to_front(node)\n            return\n\n        node = Node(key, value)\n        self.cache[key] = node\n        self._add_to_front(node)\n\n        if len(self.cache) > self.capacity:\n            lru = self.tail.prev\n            self._remove(lru)\n            del self.cache[lru.key]\n\n\n# Test 1: basic eviction order\ncache = LRUCache(2)\ncache.put(1, 1)\ncache.put(2, 2)\nassert cache.get(1) == 1\ncache.put(3, 3)\nassert cache.get(2) == -1\ncache.put(4, 4)\nassert cache.get(1) == -1\nassert cache.get(3) == 3\nassert cache.get(4) == 4\n\n# Test 2: updating a key refreshes its recency\ncache = LRUCache(2)\ncache.put(1, 10)\ncache.put(2, 20)\ncache.put(1, 11)\ncache.put(3, 30)\nassert cache.get(2) == -1\nassert cache.get(1) == 11\nassert cache.get(3) == 30\n\n# Test 3: capacity one and missing key\ncache = LRUCache(1)\ncache.put(1, 1)\ncache.put(2, 2)\nassert cache.get(1) == -1\nassert cache.get(2) == 2\nassert cache.get(99) == -1\n```\n\nBoth `get` and `put` are O(1) average time using a hash map plus a doubly linked list."}
+{"label": "ds200-faster", "task": 3, "elapsed_s": 100.8, "prompt_n": 83, "prompt_tok_s": 15.9, "gen_n": 1738, "decode_tok_s": 18.0, "draft_n": 0, "draft_n_accepted": 0, "finish": "stop", "thinking_chars": 5440, "answer_chars": 552, "reasoning": "We need answer write POSIX shell script. Need parse request: \"Write a POSIX shell script that prints the 10 largest files under a directory given as the first argument, handles file names with spaces, and prints a usage line when the argument is missing.\" Need provide script. Need consider POSIX shell, find? POSIX find supports -type f, -size? We need print 10 largest files under directory. Handle names with spaces. Need robust. Could use find \"$dir\" -type f -exec ls -l? Sorting by size. Need handle names with spaces. POSIX not sort -n? sort supports -n POSIX? sort -n yes. Need generate sizes and paths. Need handle newlines in filenames? \"handles file names with spaces\" not necessarily newlines. But POSIX shell script. Need avoid parsing ls. Use find -type f -exec? To get sizes, can use find ... -type f -printf not POSIX (GNU). POSIX find doesn't have -printf. Could use wc -c? But wc -c on file with spaces: find -exec wc -c {} + produces multiple lines, path includes spaces but wc output includes count then path, can parse? If filename has newline? Could handle spaces by quoting with NUL? POSIX find supports -exec printf? Need robust.\n\nApproaches:\n1. Use find \"$dir\" -type f -exec ls -l {} \\; then sort -k5 -nr? But ls output path with spaces after size. We can use `find ... -type f -exec ls -l {} + | sort -k5 -nr | head -n 10`. But filenames with spaces okay? sort by size column, then print ls lines. But if filename begins weird? It prints owner perms size date path. Space in path okay. It handles spaces. But maybe not truly \"largest files\" if hard? use `ls -l` includes symlinks? -type f excludes symlinks. Need size. `ls -l` output field 5 is size. sort -k5,5nr. But POSIX sort key? `sort -k5,5 -n -r`? POSIX sort -k? yes. Need numeric. But `ls -l` output for multiple files via -exec ls -l {} + can have blocks? Need careful: `ls -l` output includes total line when multiple? GNU ls when arguments multiple non-directory? Actually `ls -l file1 file2` prints one line per file no total. With `{} +`, all files. But if many files, multiple exec calls, each `ls -l` output? no total for files? Let's verify: `ls -l f1 f2` has no total? If directory args yes total for each directory. Since -type f pass files, no total. Good. Sort all lines. But filenames with newline break ls output; spaces okay. Also `ls -l` for file names with spaces will output the path as-is, spaces unquoted but entire line. Sort field 5 okay. head -n 10. But \"prints the 10 largest files\" maybe should print sizes and names. This prints full `ls -l`, acceptable? The question maybe expected output \"the 10 largest files\" not necessarily only names. We can make cleaner with `find ... -exec sh -c 'for f; do printf \"%s\\t%s\\n\" \"$(wc -c < \"$f\")\" \"$f\"; done' sh {} + | sort -n ...`. But `wc -c` may produce count only, file names with spaces handled by separate field. Need avoid command substitution with newline? Filename with newline? `wc -c < \"$f\"` returns number, then printf count tab path. If path starts `-`, no issue. If path contains newline, printf outputs newline inside path causing sort parsing issues. But request only spaces. Could use NUL for robustness but POSIX sort -z? Not POSIX. Since space only, okay.\n\nNeed print usage if missing: \n```\n#!/bin/sh\nif [ \"$#\" -eq 0 ]; then\n    printf 'Usage: %s directory\\n' \"$0\" >&2\n    exit 1\nfi\n\ndir=$1\nif [ ! -d \"$dir\" ]; then\n    printf 'Usage: %s directory\\n' \"$0\" >&2\n    exit 1\nfi\nfind \"$dir\" -type f -exec sh -c '\n  for file do\n    size=$(wc -c < \"$file\") || continue\n    printf \"%s\\t%s\\n\" \"$size\" \"$file\"\n  done\n' sh {} + | sort -n -r -k1,1 | head -n 10\n```\nNeed handle spaces: `printf \"%s\\t%s\\n\" \"$size\" \"$file\"` and sort by first field numeric. If filename contains tabs? The tab between size and name; sort key first field. Display names with spaces. Good. But if file path contains newline sort/head might break. Not required. Could use `find ... -exec sh -c` with `{} +` but `find` with `{} +` may pass many files, command line length. POSIX. `wc -c` reads file. If file is unreadable, skip? `continue` in while? It's in for loop; `continue` works. Need `wc -c < \"$file\"` output may include leading spaces? GNU wc outputs number no leading? It may include spaces? `wc -c` prints count. sort -n handles leading spaces. But using `sort -n -r -k1,1`, if first field numeric. If size missing due error? We skip. Need if `wc` fails? continue. Fine.\n\nPotential issue: `sort -n -r -k1,1` syntax POSIX: sort [-n] [-r] [-k keydef]? Key definition `-k1,1`. Yes. But `-k1,1` means start at field 1 end field 1. POSIX sort supports `-k`? POSIX sort has `-k keydef`? I recall POSIX sort: `sort [-m] [-o output] [-k keydef]...`? POSIX 2018 sort has `-k keydef`. yes.\n\nBut if `head -n 10`? POSIX `head -n 10` is allowed? POSIX head supports `-n number`? Historically `head -n 10` not in old POSIX? POSIX head has `-n number` yes? Let's confirm: POSIX `head [-n number] [file]`; yes. Alternatively `head -10` for older. Use `head -n 10`.\n\nCould avoid ls. Need maybe script prints largest files under directory recursively. \"under a directory\" likely includes all files recursively. Need mention.\n\nBut need be careful with filenames containing newline. The task specifically says \"handles file names with spaces\". So no need newline. But can make more robust with a POSIX approach using `find` and `-exec` and a sort with NUL?\n\nI have thought about this long enough; time to give my answer.\n", "answer": "#!/bin/sh\n\nif [ \"$#\" -eq 0 ]; then\n    printf 'Usage: %s directory\\n' \"$0\" >&2\n    exit 1\nfi\n\ndir=$1\n\nif [ ! -d \"$dir\" ]; then\n    printf 'Usage: %s directory\\n' \"$0\" >&2\n    exit 1\nfi\n\nfind \"$dir\" -type f -exec sh -c '\n    for file do\n        size=$(wc -c < \"$file\") || continue\n        printf \"%s\\t%s\\n\" \"$size\" \"$file\"\n    done\n' sh {} + |\nsort -n -r -k1,1 |\nhead -n 10\n\nThis prints each file\u2019s size and path, using a tab separator. File names containing spaces are preserved because the path is quoted in the shell loop and passed through `printf`."}