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The sum of outcomes for rolling an N-sided dice K times. #11463
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| Original file line number | Diff line number | Diff line change |
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| import numpy as np | ||
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| def outcome_of_rolling_n_sided_dice_k_time(n_side: int, k_time: int) -> float: | ||
| """ | ||
| The sum of outcomes for rolling an N-sided dice K times. | ||
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| This function returns a list. The last two elements are the | ||
| range of probability distribution. | ||
| The range is: 'k_time' to 'k_time*n_side' | ||
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| Other elements contain probabilities for getting a summation | ||
| from 'k_time' to 'k_time*n_side'. | ||
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| Algorithm Explanation: | ||
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| 1. Explanation of range: | ||
| When we are rolling a six-sided dice the range becomes | ||
| 1 to 6. | ||
| While rolling 5 times range becomes 5 to 30. | ||
| The sum outcomes become 5 when all rolling finds 1. | ||
| 30 happens when all rolling finds 6. | ||
| 1 is the minimum and 6 is the maximum of side values | ||
| for a 6 sided dice. Therefore, the range is 5 to 30. | ||
| Therefore, the range is k to n*k. | ||
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| 2. Explanation of probability distribution: | ||
| Say we are rolling a six-sided dice 2 times. | ||
| for 0 roll, the outcome is 0 with probability 1. | ||
| For the first roll, the outcome is 1 to 6 equally distributed. | ||
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| For the second roll, each previous outcome (1-6) will face | ||
| an addition from the second rolling (1-6). | ||
| If the first outcome is (known) 3, then the probability of | ||
| getting each of 4 to 9 will be 1/6. | ||
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| While rolling 2 dice simultaneously, | ||
| the sum becomes 2 for two 1 outcomes. But the sum becomes | ||
| 3 for two different outcome combinations (1,2) and (2,1). | ||
| The probability of getting 2 is 1/6. | ||
| The probability of getting 3 is 2/6 | ||
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| Link to rolling two 6-sided dice combinations: | ||
| https://www.thoughtco.com/ | ||
| probabilities-of-rolling-two-dice-3126559 | ||
| That phenomenon is the same as the convolution. | ||
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| The algorithm can be used in playing games or solving | ||
| problems where the sum of multiple dice throwing is needed. | ||
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| NB: a) We are assuming a fair dice | ||
| b) Bernoulli's theory works with getting the probability of | ||
| exactly 3 sixes while rolling 5 times. It does not work directly | ||
| with the sum. The same sum can come in many combinations. | ||
| Finding all of those combinations and applying Bernoulli | ||
| is more computationally extensive. | ||
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| I used that method in my paper to draw the distribution | ||
| Titled: Uncertainty-aware Decisions in Cloud Computing: | ||
| Foundations and Future Directions | ||
| Journal: ACM Computing Surveys (CSUR) | ||
| link: https://dl.acm.org/doi/abs/10.1145/3447583 | ||
| The PDF version of the paper is available on Google Scholar. | ||
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| >>> import numpy as np | ||
| >>> outcome_of_rolling_n_sided_dice_k_time(.2,.5) | ||
| Traceback (most recent call last): | ||
| ... | ||
| ValueError: The function only accepts integer values | ||
| >>> outcome_of_rolling_n_sided_dice_k_time(-1,5) | ||
| Traceback (most recent call last): | ||
| ... | ||
| ValueError: Side count should be more than 1 | ||
| >>> outcome_of_rolling_n_sided_dice_k_time(3,-2) | ||
| Traceback (most recent call last): | ||
| ... | ||
| ValueError: Roll count should be more than 0 | ||
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| >>> outcome_of_rolling_n_sided_dice_k_time(2,2) | ||
| array([0.25, 0.5 , 0.25, 2. , 4. ]) | ||
| >>> outcome_of_rolling_n_sided_dice_k_time(2,4) | ||
| array([0.0625, 0.25 , 0.375 , 0.25 , 0.0625, 4. , 8. ]) | ||
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| """ | ||
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| if n_side != int(n_side) or k_time != int(k_time): | ||
| raise ValueError("The function only accepts integer values") | ||
| if n_side < 2: | ||
| raise ValueError("Side count should be more than 1") | ||
| if k_time < 1: | ||
| raise ValueError("Roll count should be more than 0") | ||
| if k_time > 100 or n_side > 100: | ||
| raise ValueError("Limited to 100 sides or rolling to avoid memory issues") | ||
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| prob_dist = 1 | ||
| dist_step = np.ones(n_side, dtype=float) / n_side | ||
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| iter1 = 0 | ||
| while iter1 < k_time: | ||
| prob_dist = np.convolve(prob_dist, dist_step) | ||
| iter1 = iter1 + 1 | ||
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| prob_index = np.concatenate((prob_dist, np.array([k_time, k_time * n_side]))) | ||
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| return prob_index | ||
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| """ | ||
| # Extra code for the verification | ||
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| dist_index = outcome_of_rolling_n_sided_dice_k_time(6, 3) | ||
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| the_range = range(int(dist_index[-2]), int(dist_index[-1]+1)) | ||
| probabilities = dist_index[:-2] | ||
| print("Indexes:",the_range) | ||
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| print("Distribution:",probabilities, "Their summation:",np.sum(probabilities)) | ||
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| import matplotlib.pyplot as plt | ||
| plt.bar(the_range, probabilities) | ||
| plt.xlabel("Summation of Outcomes") | ||
| plt.ylabel("Probabilities") | ||
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| """ | ||
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CONTRIBUTING.md says that variable names should be self-documenting.